What is the solution to the equation 1/square root of 8 = 4^(m + 2)?
m = −15/4
m = −11/4
m = 5/4
m = 9/4

Question

matthewe1903 matthewe1903

01-05-2018
Mathematics

contestada

What is the solution to the equation 1/square root of 8 = 4^(m + 2)?
m = −15/4
m = −11/4
m = 5/4
m = 9/4

Respuesta :

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sqdancefan sqdancefan · Answer 1 · 2018-05-01T21:53:58+02:00

sqdancefan sqdancefan

01-05-2018

Take the log (base 4) of both sides of the equation.
[tex]\log_{4}(\frac{1}{\sqrt{8}}) = m + 2[/tex]
[tex]\frac{-1}{2} \log_{4}(4^{\frac{3}{2}})-2 = m[/tex]
[tex]-2 \frac{3}{4}= m[/tex]

The appropriate choice is ...
m = -11/4

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17emilymar247 17emilymar247 · Answer 2 · 2018-05-02T21:33:48+02:00

17emilymar247 17emilymar247

02-05-2018

I agree with the other person, the answer is -11/4

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What is the solution to the equation 1/square root of 8 = 4^(m + 2)? m = −15/4 m = −11/4 m = 5/4 m = 9/4

Respuesta :

Otras preguntas

What is the solution to the equation 1/square root of 8 = 4^(m + 2)?
m = −15/4
m = −11/4
m = 5/4
m = 9/4