trinixx18 trinixx18

13-04-2018
Mathematics

contestada

To evaluate ∫ 3x2 cos (2x3 - 4) dx, it is necessary to let A. u = 6x. B. u = 6x2 C. u = 2x3 -4 D. u = 3x2

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surjithayer10otahza surjithayer10otahza

13-04-2018

put 2x^3-4=u
2*3x^2 dx=du
3x^2 dx=1/2 du
∫ cos du=sin u+c
I=1/2∫cosu du=1/2 sin u+c
=1/2 sin (2x^3-4)+c

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