Respuesta :

wizard123
Solve with substitution:

Let u = cos^2(4x)
du = -8sin(4x) cos(4x) dx

[tex]-\frac{1}{8} \int u^{1/2} du \\ \\ = -\frac{1}{8} (\frac{2}{3} u^{3/2}) + C \\ \\ = -\frac{1}{12} cos^3 (4x) + C[/tex]

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