intercept ⇒ when f(x) = 0
f(x) = 3x² - 12x - 1
3x² - 12x - 1 = 0
[tex]x = \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a} [/tex]
[tex]x = \dfrac{-(-12)\pm \sqrt{(-12)^2 - 4(3)(-1)} }{2(3)} [/tex]
[tex]x = 4.08 \ or \ x= -0.08[/tex]
Answer: The two x-intercepts are (4.08, 0) and (-0.08, 0)
