saulmaple15 saulmaple15
  • 15-03-2018
  • Chemistry
contestada

4130 J of energy 52g water 10 c initial specific heat 4.18 J waht would the final temperature be

Respuesta :

jamuuj jamuuj
  • 25-03-2018
Heat energy = mass × specific heat capacity × change in temperature.
Heat energy = 4130 J, specific heat capacity of water = 4.18 J/g/C, the mass of water = 52 g, if final temperature is T
4130 = 52 × 4.18 ×(T-10)
4130 = 217.36 T - 2173.6
217.36 T = 6303.6
    T = 29
Therefore the final temperature is 29 °C
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