Answer:
111.8 mL is the volume of this piece of metal.
Explanation:
Mass of the unknown sample = m = 550.0 g
Volume of the unknown sample = V = ?
Density of the sample,d = 4.920 g/mL
[tex]Density=\frac{Mass}{Volume}[/tex]
[tex]d=\frac{m}{V}=4.920 g/mL=\frac{550.0 g}{V}[/tex]
[tex]V=\frac{550.0 g}{4.920 g/mL}=111.78 mL\approx 111.8 mL[/tex]
111.8 mL is the volume of this piece of metal.