[tex] {16x}^{3} + {12x}^{2} + 4x[/tex]
If you want to divide by 4x, we need to make sure that all numbers are divisible by 4 and by x
16 is 4x4
12 is 4x3
4 is 4x1
x^3, x^2 and x all have x in them.
Step by step, divide each one by 4 and then by x.
16x^3 = 4x^2
12x^2 = 3x
4x = 1
therefore the answer is
[tex]4 x{}^{2} +3x + 1[/tex]
