bswhittaker2007 bswhittaker2007
  • 13-04-2024
  • Mathematics
contestada

Hi everyone this question attached on algebraic fractions on mathswatch is really stumping me and my friend. Would really appreciate some help.

Thanks everyone

Hi everyone this question attached on algebraic fractions on mathswatch is really stumping me and my friend Would really appreciate some help Thanks everyone class=

Respuesta :

jimrgrant1 jimrgrant1
  • 13-04-2024

Answer:

a = 2 , b = 6

Step-by-step explanation:

We require to express the 3 terms with a common denominator

The common denominator is (x + 1)(x - 1) = x² - 1, then

[tex]\frac{2(x^2-1)-(x-1)(x+3)-(x+1)(x-5)}{x^2-1}[/tex] ← distribute parenthesis on numerator

= [tex]\frac{2x^2-2-(x^2+2x-3)-(x^2-4x-5)}{x^2-1}[/tex]

= [tex]\frac{2x^2-2-x^2-2x+3-x^2+4x+5}{x^2-1}[/tex] ← collect like terms on numerator

= [tex]\frac{2x+6}{x^2-1}[/tex] ← in the form [tex]\frac{ax+b}{x^2-1}[/tex]

with a = 2 and b = 6

Answer Link

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