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Evaluate the Riemann sum for [tex]f(x)=2x^2+3x-4[/tex] on the interval (0, 4) using 4 rectangles and the right end point. And then do the same using the left end point.

Respuesta :

nikvist

Answer:

Step-by-step explanation:

[tex]f(x)=2x^2+3x-4\\f(0)=-4\\f(1)=1\\f(2)=10\\f(3)=23\\f(4)=40\\\\left \quad Riemann\quad sum=f(0)+f(1)+f(2)+f(3)=30\\right \quad Riemann\quad sum=f(1)+f(2)+f(3)+f(4)=74[/tex]

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