Here is a similar problem that you can follow:
[tex](5x+2)^2=7 \newline 5x+2=\pm\sqrt{7} \newline 5x=-2\pm\sqrt{7} \newline x=\frac{-2\pm\sqrt{7}}{5}[/tex]
Your answer choices write solutions in an equivalent format, such as
[tex]x=\frac{\sqrt{7}-2}{5}[/tex] and [tex]x=\frac{-\sqrt{7}-2}{5}[/tex]
