swhrish
swhrish
14-08-2017
Mathematics
contestada
How would I solve this?
Respuesta :
apologiabiology
apologiabiology
14-08-2017
subsitute 7 for x
√(2k²+17)-7=0
add 7 to both sides
√(2k²+17)=7
squaer both sides
2k²+17=49
minus 17 both sides
2k²=32
divide both sides by 2
k²=16
square both sides
k=+/-4
we are given that k>0 so k=4
answer is C
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