cello10
cello10 cello10
  • 13-08-2017
  • Mathematics
contestada

Find the equation of the line tangent to y = –x2 + 3x + 8 at x = 2.

Find the equation of the line tangent to y x2 3x 8 at x 2 class=

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apologiabiology
apologiabiology apologiabiology
  • 14-08-2017
take derivitive

y'=-2x+3

at x=2
y'=-2(2)+3
y'=-4+3
y'=-1

slope is -1

find the value of y when x=2

y=-(2)^2+3(2)+8
y=-4+6+8
y=10

(2,10) and slope is -1

use point slope form
y-y1=m(x-x1)
a point is (x1,y1) and the slope is m

so
y-10=-1(x-2)
y-10=-x+2
y=-x+12

2nd option
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