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If 824 grams of NH3 and excess oxygen gas react to produce nitrogen oxide and water, how many moles of nitrogen oxide are formed?
2_ NH3 + 3 O2 3 Hâ‚‚O + 2 N2O3

Respuesta :

Answer:

The moles of N2O3 will be the same as the moles of NH3

Explanation:

The molar mass of NH3 (ammonia) is approximately 17 grams/mol. So, for 824 grams of NH3:

824g/(17g/mol)

Now, calculate that to find the moles of NH3.

Next, we look at the balanced chemical equation. According to the equation, 2 moles of NH3 react to produce 2 moles of N2O3.

2NH3+3O2→3H2O+2N2O3

So, if we know the moles of NH3, we can directly find the moles of N2O3. Since the ratio is 1:1, the moles of N2O3 will be the same as the moles of NH3.

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