Respuesta :

mergl
2.8(2/1)=5.6 moles of AgNO3 would be  needed

Answer:

5.6 moles of AgNO3 is required to produce 2.8 moles of Cu(NO3)2

Explanation:

Cu + 2AgNO3 Cu(NO3)2 + 2Ag

Before solving this one must make sure the equation is balanced.  From the balance equation you could notice that the AgNo3(silver nitrate) has 2 moles while the Cu(NO3)2 has 1 mole.

If 2 moles = 1 mole

    ?   = 2.8 moles

cross multiply 2.8 x 2 = 5.6 moles    

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