Respuesta :

Nirina7
the answer 
Cu → cu2+   +  2e– this equation represents oxydation half-reaction of Cu II

Explanation:

In a reduction-half reaction, there is gain of electrons.

For example, [tex]Ag^{+} + 1e^{-} \rightarrow Ag[/tex]

Whereas in an oxidation-half reaction, there is loss of electrons.

For example, [tex]Cu \rightarrow Cu^{2+} + 2e^{-}[/tex]

Thus, we can conclude that the equation Cu → cu2 2e–  represents oxidation-half reaction.