To solve for this, you can create a series of two equations [tex] \left \{ {{y+x=15 \frac{3}{10} } \atop {y-x= 8\frac{5}{10} }} \right. [/tex]
After that, you solve one of the equations for x and plug it into the other equation. [tex] \left \{ {{x=15 \frac{3}{10}-y } \atop {y-x= 8\frac{5}{10} }} \right. [/tex]
[tex] {2y-15 \frac{3}{10}= 8\frac{5}{10} [/tex]
Then, solve for variable y [tex] {2y=23 \frac{8}{10} [/tex] [tex] {y=11\frac{9}{10} [/tex]
Then, you plug in this value for y into one of the original equations