Diameter has endpoints (-5,4) and (3, -6).
the endpoints of the diameter = (-5,4) and (3,-6)
The length of diameter can be calculated by sqrt 10,11
Distance between two coordinates (-5,4) and (3,-6).
Distance formula is express as
[tex]\begin{gathered} \text{Distance = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^1^{}} \\ \text{Distance}=\sqrt[]{(3-(-5))+(-6+(4))} \\ \text{Diamter = }\sqrt[]{8-(-2)} \\ \text{Diameter = }\sqrt[]{10} \end{gathered}[/tex]Diameter = sqrt 10
Answer: Diameter = sqrt 10
