jordankhood21
jordankhood21 jordankhood21
  • 13-02-2017
  • Mathematics
contestada

What is the equation of a circle whose center is at the origin and whose radius is 16? x2 + y2 = 4 x2 + y2 = 16 x2 + y2 = 256

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ApusApus ApusApus
  • 14-05-2019

Answer:

3. [tex]x^2+y^2=256[/tex]

Step-by-step explanation:

We are asked to find the equation of circle, whose center is at the origin (0,0) and whose radius is 16.

We know that standard form of a circle is in form: [tex](x-h)^2+(y-k)^2=r^2[/tex], where,

[tex](h,k)[/tex] = Center of circle,

r = Radius of circle.

Upon substituting our given values in standard form of circle, we will get

[tex](x-0)^2+(y-0)^2=16^2[/tex]

[tex]x^2+y^2=256[/tex]

Therefore, 3rd option is the correct choice.

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sierra3324
sierra3324 sierra3324
  • 15-12-2020

Answer:

x^2+y^2=256

hope this helps :)

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