emmaveiga05 emmaveiga05

15-09-2022
Physics

contestada

If a ball leaves the ground with a velocity of 4.67 m/s,
how high does the ball travel?

Respuesta :

Benionmo Benionmo

16-09-2022

Answer:

[tex]Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\[/tex]

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