The 6th term of the sequence is a₆ = 24
Given, a₁ = 4 and an = a(n-1) + 4
Therefore, a₂ = a(2-1) + 4
a₂ = a₁ + 4
a₂ = 4 + 4
a₂ = 8
a₃ = a (3-1) + 4
a₃ = a₂ + 4
a₃ = 12
a₄ = a₃ + 4
a₄ = 12 + 4
a₄ = 16
a₅ = a₄ + 4
a₅ = 16 + 4
a₅ = 20
a₆ = a₅ + 4
a₆ = 20 + 4
a₆ = 24
Therefore, the sixth term of the sequence is 24.
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