Respuesta :

Answer:  -1.67 KJ

Explanation:

Given- m of water= 21g

           Final temperature- 67°C

           Initial temperature- 86°C

           Specific heat capacity of water ( c)= 4.182 J/g°C

Solution

Q= mcΔT

Q= 21g* 4.182J/g°C*(67°C-86°C) = -1669J