k9kqrcxns5
k9kqrcxns5 k9kqrcxns5
  • 15-07-2022
  • Mathematics
contestada

Please help fast mathswatch!!

Please help fast mathswatch class=

Respuesta :

subhojitguin2004
subhojitguin2004 subhojitguin2004
  • 15-07-2022

Answer:

The reqiured volume is 451 cm³.

Step-by-step explanation:

The volume is = cross section × height

= 41 × 11 cm³

= 451 cm³

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