8gra9eabqv
8gra9eabqv 8gra9eabqv
  • 13-06-2022
  • Mathematics
contestada

This is a simultaneous equation and I need help
5x+3y=27
2x+y=10

Respuesta :

jimrgrant1 jimrgrant1
  • 13-06-2022

Answer:

(3, 4 )

Step-by-step explanation:

5x + 3y = 27 → (1)

2x + y = 10 ( subtract 2x from both sides )

y = 10 - 2x → (2)

substitute y = 10 - 2x into (1)

5x + 3(10 - 2x) = 27

5x + 30 - 6x = 27

- x + 30 = 27 ( subtract 30 from both sides )

- x = - 3 ( multiply both sides by - 1 )

x = 3

substitute x = 3 into (2)

y = 10 - 2(3) = 10 - 6 = 4

solution is (3, 4 )

Answer Link
kendallsykes10p4b3jl
kendallsykes10p4b3jl kendallsykes10p4b3jl
  • 13-06-2022
Your answer is:

X = 3
Y = 4

Ordered pair form: (3,4)
Answer Link

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