Respuesta :

loneguy

[tex]\left(\sqrt x - \sqrt{3y} \right) \left(\sqrt x + \sqrt{3y} \right)\\\\=\left(\sqrt x\right)^2 - \left(\sqrt{3y} \right)^2\\\\=x -3y[/tex]

fieryanswererft

x - 3y

Solving Stepwise:

[tex]\hookrightarrow \sf \left(\sqrt{x}-\sqrt{3y}\right)\left(\sqrt{x}+\sqrt{3y}\right)[/tex]

  • [tex]\sf apply \ the \ rule : \bold{\left(a-b\right)\left(a+b\right)=a^2-b^2}[/tex]

[tex]\hookrightarrow \sf \left(\sqrt{x}\right)^2-\left(\sqrt{3y}\right)^2[/tex]

[tex]\hookrightarrow \sf x-3y[/tex]

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