Solution:
Let the quantity of alloy required = m g
Then 26 % of m =260 g
[tex]\small\bold\green{⇒}\small\bold{\frac{(26)}{100} × m = 260 g}[/tex]
[tex]\small\bold\green{⇒}\small\bold{m = \frac{(260 × 100)}{26} g}[/tex]
[tex]\small\bold\green{⇒}\small\bold{m = \frac{26000}{26} g}[/tex]
[tex]\small\bold\green{⇒}\small\bold{m = 1000 g}[/tex]
