Respuesta :

Answer:

A) [tex]\frac{cos^2A}{sinA}[/tex]

Step-by-step explanation:

[tex]cscA-sinA\\\\\frac{1}{sinA}-sinA\\ \\\frac{1}{sinA}-\frac{sin^2A}{sinA}\\ \\ \frac{1-sin^2A}{sinA}\\ \\\frac{cos^2A}{sinA}[/tex]

Answer:

1st option

Step-by-step explanation:

Using the identities

csc x = [tex]\frac{1}{sinx}[/tex]

sin² x + cos²x = 1 ⇒ cos²x = 1 - sin²x

then

csc A - sinA

= [tex]\frac{1}{sinA}[/tex] - sinA

= [tex]\frac{1-sin^2A}{sinA}[/tex]

= [tex]\frac{cos^2A}{sinA}[/tex]