jqin2007
jqin2007
13-02-2022
Mathematics
contestada
How to solve:
3*9^(2n) = (3^(n +1))^3
Respuesta :
jonathanreaves
jonathanreaves
13-02-2022
3×9
n+1
−9×3
2n
=
3×3
2n+3
−(3
2
)
n+1
3×(3
2
)
n+1
−3
2
×3
2n
=
3
1+2n+3
−3
2n+2
3
1+2n+2
−3
2+2n
=
3
4+2n
−3
2n+2
3
3+2n
−3
2+2n
=
3
2n
(3
4
−3
2
)
3
2n
(3
3
−3
2
)
=
81−9
27−9
=
72
18
=
4
1
Answer Link
731427
731427
13-02-2022
Answer:
3
Step-by-step explanation:
3*9^(2n) = (3^(n +1))^3
= 3×9^0^3
= 3×9^0
= 3×1
= 3
Answer Link
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