noname12345678 noname12345678
  • 16-01-2017
  • Mathematics
contestada

Which is a correct factorization of 391?
(20 - 3)^2
(20 - 3) (20 + 3)
(20 - 9)(20 + 9)
(20 + 3)^2

Respuesta :

Аноним Аноним
  • 16-01-2017
Let's see,

1.(20 - 3)^2
   (20 - 3)^2= 20 - 3 = 17 * 17 = 289

2.(20 - 3) (20 + 3)
   (20 - 3) (20 + 3) = 20 -3 =17 , 20 + 3 = 23 , (17)*(23) = 391.

3.(20 - 9) (20 + 9)
   (20 - 9) (20 + 9) = 20 - 9 = 11 , 20 + 9 = 29 , (11)*(29)= 319.

4.(20 + 3)^2
   (20 + 3)^2= 20 + 3 = 23 * 23 = 529

Answer: #2, (20 - 3) (20 + 3)

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