Answer:
x [tex]\leq[/tex] -3
Step-by-step explanation:
Make common denominators
[tex]\frac{2x}{6}[/tex] - [tex]\frac{3x-3}{6}[/tex][tex]\geq[/tex][tex]\frac{6}{6}[/tex]
Use the numerators only
2x - (3x - 3) [tex]\geq[/tex] 6
Distribute
2x - 3x + 3 [tex]\geq[/tex] 6
-x + 3 [tex]\geq[/tex] 6
Subtract 3 from both sides
-x [tex]\geq[/tex] 3
