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  • 13-11-2021
  • Mathematics
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find the derivative of (Cosx/1+sinx)^5​

Respuesta :

Skultrix
Skultrix Skultrix
  • 13-11-2021

Use the Chain Rule:

[tex]\frac{d}{dx} [f(g(x))] = f'(g(x)) * g'(x)[/tex]

Given Information:

[tex]f(x) = x^5\\ g(x) = \frac{cos(x)}{1} +sin(x)\\ f(g(x)) = ( \frac{cos(x)}{1} +sin(x))^5\\ \\ f'(x)=5x^4\\ g'(x)=\frac{-sin(x)}{1} + cos(x)\\f'(g(x))*g'(x)=5(\frac{cosx)}{1} + sin(x))^4*(\frac{-sin(x)}{1} + cos(x))[/tex]

The answer is:

[tex]5(\frac{cosx)}{1} + sin(x))^4*(\frac{-sin(x)}{1} + cos(x))[/tex]

Answer Link

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