halfbloodprince2378 halfbloodprince2378
  • 12-11-2021
  • Mathematics
contestada

[Please, help me. I need it quickly]
If cosA+sinA=√2, then prove A=45°.

Respuesta :

codskrueg codskrueg
  • 12-11-2021

Step-by-step explanation:

Start by squaring both sides

cosA+sinA=[tex]\sqrt{2}[/tex]

[tex]cos^2A+2cosAsinA+sin^2A=2[/tex]

Apply Trig identity

[tex]cos^2x+sin^2x=1[/tex]

2cosAsinA+1=2

2cosAsinA=1

Apply Trig Identity

2cosxsinx=sin(2x)

sin(2A)=1

2A=arcsin1

arcsin(1) is a known value [tex]\frac{\pi }{2}[/tex]

2A=[tex]\frac{\pi }{2}[/tex]

A=[tex]\frac{\pi }{4}[/tex]

[tex]\pi[/tex] [tex]radians=180^o[/tex]

A=[tex]\frac{180^o}{4}[/tex]=[tex]45^o[/tex]

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