hahabonner1
hahabonner1 hahabonner1
  • 11-10-2021
  • Mathematics
contestada

Find the value of k so that the remainder is 1 when x^3+5x^2+kx-8 is divided by (x-3)
K=

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LammettHash
LammettHash LammettHash
  • 12-10-2021

By the remainder theorem, the remainder upon dividing [tex]x^3+5x^2+kx-8[/tex] by [tex]x-3[/tex] is given by the value of this expression when x = 3 :

[tex]3^3 + 5\cdot3^2 + 3k - 8 = 1[/tex]

Solve for k :

[tex]27 + 45 + 3k - 8 = 1 \\\\ 3k = -63 \\\\ \boxed{k = -21}[/tex]

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