WolfLover181957
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  • 15-12-2016
  • Mathematics
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The function f(x) = ax^r satisfies f(2) = 1 and f(32) = 4. Find r.

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Аноним Аноним
  • 15-12-2016
(2) = 1 ==> a%2A2%5Er+=+1 <-------Equation A while f(32) = 4 ==> a%2A32%5Er+=+4. <------Equation B. 
 Divide Equation B by corresponding sides of equation A: ==> 16%5Er+=+4 ==> r = 1/2. BTW, a+=+1%2Fsqrt%282%29, and the function is f%28x%29+=+sqrt%28x%2F2%29 
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