Answer:
(m-n)
Step-by-step explanation:
1st expression=
[tex] = {m}^{2} - {n}^{2} \: \: \: \: \: \: \: \: \: \: [/tex]
=(m-n) (m+n)
2nd expression=
[tex] ({m - n})^{2} [/tex]
=(m-n)(m-n)
therefore H.C.F=(m-n)
taking common (m-n)
