Answer:
[tex]a= \frac{9}{B+Q^2}[/tex]
Step-by-step explanation:
Given;
-Ba+9=Q²a
To solve for "a", make "a" the subject of the formula.
First, collect similar terms together;
-Ba - Q²a = -9
multiply through by "-1" to remove the negative sign;
Ba + Q²a = 9
factor out a;
a(B + Q²) = 9
divide both sides of the equation by "(B + Q²) ";
[tex]\frac{a(B+Q^2)}{B+Q^2} = \frac{9}{B+Q^2} \\\\a = \frac{9}{B+Q^2}[/tex]
Therefore, the value of "a" in the given expression is [tex]\frac{9}{B+Q^2}[/tex]
