Respuesta :

maacastrobr

Answer:

21.63 %

Explanation:

The molar mass of Mn₃[Mn(CO)₄]₃ is 665.64 g/mol.

Let's assume we have 1 mol of Mn₃[Mn(CO)₄]₃, if that were the case then we would have 665.64 grams.

There are 12 C moles per Mn₃[Mn(CO)₄]₃, with that in mind we calculate the weight of 12 C moles:

  • 12 mol C * 12 g/mol = 144 g

Finally we calculate the mass percent of carbon:

  • 144 g / 665.64 g * 100% = 21.63 %

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