Respuesta :

rakshaprakash11

Answer:

3x^2+14x+8=0

(3x^2+12x) (2x+8)=0

3x(X+4) 2(X+4)=0

so, (3x+2) (X+4)=0

either 3x+2=0

X= -2/3

or X+4=0

X= -4

now sum of solutions so

-2/3+-4

(-2+-12)/3

-14/3
If your looking for the “X”, X=-1

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