rachelsilva99
rachelsilva99 rachelsilva99
  • 13-05-2021
  • Mathematics
contestada

In triangle $DEF,$ $\angle D = 30^\circ,$ $\angle F = 60^\circ,$ and $EF = 6.$ Find $DE + DF.$

In triangle DEF angle D 30circ angle F 60circ and EF 6 Find DE DF class=

Respuesta :

sbina sbina
  • 13-05-2021

Answer:

22.39

Step-by-step explanation:

angle D + angle F + angle E = 180 (angle of triangle)

30 +60 + E = 180

E = 180 - 90

E = 90

so triangle DEF is right angled triangle

we know that,

sin 30 = EF /DF

OR, 1/2 = 6/ DF

OR, DF= 12

again,

cos 30 = De/DF

root3 /2 = DE /12

DE= 10.39

hence DF +DE

= 12 + 10.39

= 22. 39

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