Answer:
[tex]\dfrac{17}{13}[/tex]
Step-by-step explanation:
Given that,
r(x) = 3x - 1 and s(x) = 2x + 1
We need to find an expression equivalent to [tex]\dfrac{r}{s}(6)[/tex].
We know that,
[tex]\dfrac{r}{s}(6)=\dfrac{r(6)}{s(6)}[/tex]
Put x = 6 in the above expression
[tex]=\dfrac{3(6)-1}{2(6)+1}\\\\=\dfrac{18-1}{12+1}\\\\=\dfrac{17}{13}[/tex]
So, the equivalent expression is equal to [tex]\dfrac{17}{13}[/tex].
