lukecoupland4734 lukecoupland4734

13-04-2021
Physics

contestada

1.

If a force of 40N is applied for 0.2 sec

to change the momentum of a

volleyball, what is the impulse?

Respuesta :

Muscardinus Muscardinus

14-04-2021

Answer:

J = 8 kg-s

Explanation:

Given that,

Force, F = 40 N

Time, t = 0.2 s

We need to find the impulse. We know that,

Impulse, J = F×t

So,

J = 40 × 0.2

J = 8 kg-s

So, the impulse is 8 kg-s.

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