sydneylotas sydneylotas
  • 11-04-2021
  • Mathematics
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Determine the zeros of the quadratic function
f(x) = (x + 6)^2 – 9

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SMARTIEYY
SMARTIEYY SMARTIEYY
  • 11-04-2021
-9 and -3

i hope this helps
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XxTheLegendxX
XxTheLegendxX XxTheLegendxX
  • 11-04-2021

[tex]{ \huge{ \underline{ \rm{Given}}}}[/tex]

[tex]{ \large{ \sf{f(x) = (x + 6) {}^{2} - 9 = 0}}}[/tex]

[tex]{ \large{ \bf{ \underline{Formula = { \underline{a {}^{2} - b {}^{2} = (a + b)(a - b)}}}}}}[/tex]

[tex]{ \large{ \sf{(x + 6) {}^{2} - (3) {}^{2} = 0}}} [/tex]

[tex]{ \large{ \sf{(x + 6 + 3)(x + 6 - 3) = 0}}}[/tex]

[tex]{ \large{ \sf{(x + 9)(x - 3) = 0}}}[/tex]

[tex]{ \large{ \therefore{ \sf{Zeros = x ={ \boxed{ \sf( - 9 \: \: and \: - 3)}}} \: \: Ans.}}}[/tex]

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