jarashi258 jarashi258
  • 15-03-2021
  • Mathematics
contestada

If (x+1),6x,48,192 are in proportion,find the value of x

Respuesta :

andromache andromache
  • 20-03-2021

Answer:

the value of x is 2

Step-by-step explanation:

The computation of the value of x is shown below:

a:b  = c:d

where

a = x + 1

b = 6x

c = 48

d = 192

Now

[tex]\frac{x+1}{6x} = \frac{48}{192} \\\\\frac{x+1}{6x} = \frac{1}{4}\\\\4x + 4 = 6x\\\\4 = 6x - 4x\\\\4 = 2x\\\\x = \frac{4}{2}\\\\x = 2[/tex]

Hence, the value of x is 2

Therefore the same would be considered and relevant too

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