Answer:
The limit is true and it exists
Step-by-step explanation:
Given the limit [tex]{\displaystyle \lim _{n\to \infty }{\frac {1}{n}}=0}[/tex]
To show that the given limit is true, we will simply replace n with ∞
On substituting
[tex]{\displaystyle \lim _{n\to \infty }{\frac {1}{n}}=0}\\ = \frac{1}{\infty}\\= 0\\[/tex]
Hence the given limit is true and it exists since we got a finite value. Note that for any constant a, lim n ->∞ a/n = 0
