Answer:
the average force the blade exerts on the log is 1791.05 N.
Explanation:
Given;
mass of the ax head, m = 4 kg
speed of the ax, v = 3 m/s
depth traveled into the log, d = 0.01 m
The time to traveled through the depth;
[tex]s = (\frac{u+v}{2} )t\\\\0.01 = (\frac{0+3}{2} )t\\\\0.01 = 1.5t\\\\t = \frac{0.01}{1.5} \\\\t = 0.0067 \ s[/tex]
The average force the blade exerts on the log;
[tex]F = ma=\frac{mv}{t} = \frac{4 \times 3}{0.0067} = 1791.05 \ N \\\\[/tex]
Therefore, the average force the blade exerts on the log is 1791.05 N.
