Answer:
16.06 g
Explanation:
Reaction equation;
S(s) + 3F2(g) ----> SF6(s)
Number of moles of sulphur reacted = 3.5g/32g/mol = 0.11 moles
If 1 mole of sulphur yields 1 mole of SF6
Then 0.11 moles of sulphur yields 0.11 moles of SF6
Also
Number of moles of fluorine = 4.5g/38 g/mol= 0.12 moles
Hence sulphur his the limiting reactant;
Maximum amount of SF6 = 0.11 × 146 = 16.06 g
