Answer:
[tex]= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )[/tex]
Step-by-step explanation:
Given the expression [tex]log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\[/tex]
According to the law of logarithm;
loga + log b = log(ab) and log a - log b = log(a/b)
The given expression becomes;
[tex]log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )[/tex]
