Respuesta :

kianna0028
We have: 2mn^2 √5mn^2, where √ is a cubed root.

Hence, we can do (2mn^2)^3 to get 8m^3n^6. Now we'll take that into the root:

√5mn^2*8m^3n^6 = √120m^4n^8

So, √120m^4n^8 simplifies into 2mn^2 √5mn^2.
Cricetus

Answer:

[tex]2\sqrt[3]{5}m^{2}n^{4}[/tex]

Step-by-step explanation:

[tex]2mn^2\times\sqrt[3]{5}mn^2[/tex]

Let us bring the term of same type together we get

[tex]2\times\sqrt[3]{5}\times mn^2 \times mn^2[/tex]

[tex]2\sqrt[3]{5}\times mn^2\times mn^2[/tex]

[tex]2\sqrt[3]{5}\times m\times m\times n^2\times n^2[/tex]

Now here we apply the rule of exponents , which is like this

m^p\times m^q=m^{p+q}

Hence

[tex]2\sqrt[3]{5}\times m^{1+1}\times n^{2+2}[/tex]

[tex]2\sqrt[3]{5}\times m^{2}\times n^{4}[/tex]

[tex]2\sqrt[3]{5}m^{2}n^{4}[/tex]

Hence this is our answer.