andreahuff1973 andreahuff1973

13-03-2014
Mathematics

contestada

How to

Simplify 243^1.2

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Аноним Аноним

16-03-2014

[tex]243^{1,2}=243^{1\frac{2}{10}}=243^{1\frac{1}{5}}=243^{1+\frac{1}{5}}=243^1\cdot243^\frac{1}{5}=243\sqrt[5]{243}\\\\=243\sqrt[5]{3^5}=243\cdot3=729[/tex]

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zidanethernandez8 zidanethernandez8

04-02-2020

Answer:729

Step-by-step explanation:

idk

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