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11-11-2020
Mathematics

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find the equation of circle whose centre is at (3,4) and passing through (1,5)

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virtuematane virtuematane

11-11-2020

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asenamirze asenamirze

11-11-2020

Answer:

[tex](x-3)^{2} + (y-4)^{2} = r^{2} \\\\(1-3)^{2} + (5-4)^{2} = r^{2}\\r^{2} = 5 \\so the equation is \\(x-3)^{2} + (y-4)^{2} = 5[/tex]

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