Answer:
0.125 M
Explanation:
Initial volume = 300 mL
Final Volume = 300+300 = 600 mL
Initial Molarity = 0.25 M
Since the same amount of water is added to the sulfuric acid the molarity will be halved.
[tex]\dfrac{0.25}{2}=0.125\ \text{M}[/tex]
The above result can be elaborated by the following steps
[tex]\text{Initial molarity}\times\dfrac{\text{Initial volume}}{\text{Final volume}}\\ =0.25\times\dfrac{300}{600}\\ =0.25\times\dfrac{1}{2}\\ =0.125\ \text{M}[/tex]
So, the new Molarity is 0.125 M
